(2+3x)^5+(2-3x)^5=244

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Solution for (2+3x)^5+(2-3x)^5=244 equation: 



(2+3x)^5+(2-3x)^5=244

We move all terms to the left:

(2+3x)^5+(2-3x)^5-(244)=0

We add all the numbers together, and all the variables

(3x+2)^5+(-3x+2)^5-244=0

We move all terms containing x to the left, all other terms to the right

(3x+2)^5+(-3x+2)^5=244

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